This is the aptitude questions and answers section on 'Percentage' with solutions and detailed explanation. Questions in this topic are primarily on calculating percentages and its applications.

If 12% of x is equal to 6% of y, then 18% of x will be equal to how much % of y ?

Explanation:

We have ,

12% of X = 6% of Y

=> 2% of X = 1% of Y

=>(2 x 9)% of X = ( 1 x 9)% of Y

Thus, 18% of X = 9% of Y.

We have ,

12% of X = 6% of Y

=> 2% of X = 1% of Y

=>(2 x 9)% of X = ( 1 x 9)% of Y

Thus, 18% of X = 9% of Y.

If a number is 20% more than the another, how much % is the smaller number less than the first ?

Explanation:

Take a number 100,

Then the other number is 120

% the smaller number is less than the first = [(20/(120)) x 100]% = 16(2/3)%.

Take a number 100,

Then the other number is 120

% the smaller number is less than the first = [(20/(120)) x 100]% = 16(2/3)%.

If the given two numbers are respectively 7% and 28% of a third number, then what percentage is the first of the second ?

Explanation:

Here, l = 7 and m = 28

Therefore, first number = l/m x 100% of second number = 7/28 x 100% of second number = 25% of second number

Here, l = 7 and m = 28

Therefore, first number = l/m x 100% of second number = 7/28 x 100% of second number = 25% of second number

Two numbers are respectively 40% and 30% more than a third number. The second number expressed in terms of percentage of the first is ? (approx)

Explanation:

Here, x = 40 and y = 30;

Therefore second number

= [[( 100 + y)/ (100 + x )] x 100 ]% of first number

= [[( 100 + 30)/ (100 + 40 )] x 100 ]% of first number

= 92.8% of the first

Here, x = 40 and y = 30;

Therefore second number

= [[( 100 + y)/ (100 + x )] x 100 ]% of first number

= [[( 100 + 30)/ (100 + 40 )] x 100 ]% of first number

= 92.8% of the first

Two numbers are less than a third number by 40% and 47% respectively. How much per cent is the second number less than the first ?(approx)

Explanation:

Here, x = 40 and y = 47

Therefore second number

= [[(100 - y)/(100 - x )] x 100 ]% of first number

= [[(100 - 47)/(100 - 40 )] x 100 ]% of first number

i.e, 88.3% of the first.

Here, x = 40 and y = 47

Therefore second number

= [[(100 - y)/(100 - x )] x 100 ]% of first number

= [[(100 - 47)/(100 - 40 )] x 100 ]% of first number

i.e, 88.3% of the first.