Exercise: Percentage Problems

This is the aptitude questions and answers section on 'Percentage' with solutions and detailed explanation. Questions in this topic are primarily on calculating percentages and its applications.

Percentage Problems : Question 1 :
If 12% of x is equal to 6% of y, then 18% of x will be equal to how much % of y ?
7%
9%
11%
none of these
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Explanation:
We have ,
12% of X = 6% of Y
=> 2% of X = 1% of Y
=>(2 x 9)% of X = ( 1 x 9)% of Y
Thus, 18% of X = 9% of Y.
Percentage Problems : Question 2 :
If a number is 20% more than the another, how much % is the smaller number less than the first ?
12(1/3)%
16(2/3)%
16(1/3)%
none of these
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Explanation:
Take a number 100,
Then the other number is 120
% the smaller number is less than the first  = [(20/(120)) x 100]% = 16(2/3)%.
Percentage Problems : Question 3 :
If the given two numbers are respectively 7% and 28% of a third number, then what percentage is the first of the second ?
20%
25%
18%
none of these
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Explanation:
Here, l = 7 and m = 28
Therefore,  first number = l/m x 100% of second number = 7/28 x 100% of second number = 25% of second number
Percentage Problems : Question 4 :
Two numbers are respectively 40% and 30% more than a third number. The second number expressed in terms of percentage of the first is ? (approx)

95%
93%
90%
none of these
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Explanation:
Here, x = 40 and y = 30;
Therefore second number
= [[( 100 + y)/ (100 + x )] x 100 ]% of first number
= [[( 100 + 30)/ (100 + 40 )] x 100 ]% of first number
= 92.8% of the first
Percentage Problems : Question 5 :
Two numbers are less than a third number by 40% and 47% respectively. How much per cent is the second number less than the first ?(approx)
95%
88%
85%
none of these
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Explanation:
Here, x = 40 and y = 47
Therefore second number
= [[(100 - y)/(100 - x )] x 100 ]% of first number
= [[(100 - 47)/(100 - 40 )] x 100 ]% of first number
i.e, 88.3% of the first.