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Program to check if a given number is a strong number or not | FACE Prep

Published on 09 Mar 2020

Program to check if a given number is a strong number or not is discussed here. A strong number is a number in which the sum of the factorial of the digits is equal to the number itself.


check if a given number is strong number or not




C
C++
Java
Python 3

Output
Input-Enter a number:145 Output-145 is a strong number


Using Command Line Argument


The given number N, a positive integer, will be passed to the program using the first command line parameter.

If it is a strong number, the output should be YES, If it is not a prime number then output should be NO to stdout.

Other than YES or NO, no other extra information should be printed to stdout.


#include<stdio.h>
#include<stdlib.h>
int main(int a, char *b[])
{
int number, i, temp, sum = 0, factorial = 1;
number = atoi(b[1]);
temp = number;
while(number != 0)
{
int rem = number%10;
for(i=2; i<=rem; i++)
{
factorial = factorial * i;
}
sum = sum + factorial;
number = number/10;
factorial = 1;
}
if(temp == sum)
printf("YES");
else
printf("NO");
return 0;
}


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