Program to find the sum of numbers in a given range | faceprep

Program to find the sum of numbers in a given range is discussed here. Given the starting and ending interval, the sum of all the numbers in that range will be displayed as output.

For example,

Input: 1  10

Output: 55

Explanation: 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55

Algorithm to find the sum of numbers in a given range

• Input the start and end numbers.
• Initialize sum = 0.
• Repeat from i = start to and continue until i = end.
• sum = sum + i
• Print “sum”

Program to find the sum of numbers in a given range is given below.

// C program to find the sum of numbers in a given range

#include<stdio.h>
int main()
{
//fill the code
int start, end;
scanf(“%d”,&start);
scanf(“%d”,&end);
int i, sum = 0;
for(i = start; i <= end; i++)
{
sum = sum + i;
}
printf(“%d”,sum);
return 0;
}

// C++ program to find the sum of numbers in a given range

#include<iostream>
using namespace std;

int main()
{
//fill the code
int start, end;
cin >> start;
cin >> end;
int i, sum = 0;
for(i = start; i <= end; i++)
{
sum = sum + i;
}
cout << sum;
return 0;
}

// Java program to find the sum of numbers in a given range

import java.util.*;
public class Main
{
public static void main(String[] args)
{
int start, end;
Scanner sc = new Scanner(System.in);
start = sc.nextInt();
end = sc.nextInt();
int i, sum = 0;
for(i = start; i <= end; i++)
{
sum = sum + i;
}
System.out.print(sum);
}
}

# Python program to find the sum of numbers in a given range

start = int(input())
end = int(input())
sum = 0
for i in range(start, end + 1, 1):
sum = sum + i
print(sum)

Output: