Looking for IBM Placement or the IBM Business Communication Test? Here is a series of IBM Placement papers Questions based on IBM placement questions from previous years.

Tech Giants like IBM favor candidates who can perform better in aptitude based examinations. Do not get discouraged yet as you still can gain a competitive edge over other students by trying out these IBM Placement papers Questions

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**IBM Placement papers | Syllabus**

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The level of IBM Business Communication Test is moderate but might be easier for ISCE students. Passing this test is mandatory to go for the next round. At least 40% percentile is necessary to clear the cutoff

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**IBM Placement papers with Solutions**

**IBM Number series Questions**

**1. Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.****3, 10, 101,?**

**A. 10101**

**B. 10201**

**C. 10202**

**D. 11012**

Ans: C

3, 10, 101, 10202

10 = 3^2 + 1

101 = 10^2+1

10202= 101^2+1

**2. In the series 2, 6, 18, 54, …… what will be the 8th term ?**

A. 4370**B. 4374****C. 7443****D. 7434**

Ans: B

2*3 = 6, 6*3 = 18, 18*3 = 54

So a = 2 , r = 3

nth term in G.P. is ar^{n-1} = 2*2187 = 4374

**3. Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.****125,80,45,20,?**

**A. 5****B. 8****C. 10****D. 12**

Ans: A

The pattern is -45, -35, -25, -15

The next number = 20-15= 5

**4. Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.****6, 13, 25, 51, 101, ?**

**A. 201****B. 202****C. 203****D. 205**

Ans: C

The pattern is x 2 + 1, x 2 – 1, x 2 + 1, x 2 – 1,…..

So, missing term = 101 x 2 + 1 = 203

**5. Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.****1, 3, 4, 8, 15, 27, ?**

**A. 37****B. 44****C. 50****D. 55**

Ans: C

1 + 3 + 4 = 8 ;

3 + 4 + 8 = 15 ;

4 + 8 + 15 = 27 and so on.

Missing number = 8 + 15 + 27 = 50

###### Practice more IBM Number series questions

**IBM Quantitative Aptitude Questions**

**6. If log 27 = 1.431, then the value of log 9 is:**

**A. 0.934****B. 0.945****C. 0.954****D. 0.958 **

Ans: C

log 27 = 1.431

log 33

“>(33)

= 1.431

3 log 3 = 1.431

log 3 = 0.477

log 9 = log(32)= 2 log 3 = (2 x 0.477) = 0.954

**7. The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?**

**A. 0****B. 1****C. 10****D. 19**

Ans: D

Average of 20 numbers = 0.

Sum of 20 numbers = (0 x 20) = 0.

It is quite possible that 19 of these numbers may be positive and if their sum is a, then the 20th number is (- a).

**8. A student has gotten the following grades on his tests: 87, 95, 76, and 88. He wants an 85 or better overall. What is the minimum grade he must get on the last test in order to achieve that average?**

Ans: C

**3. The name is Roger Smith, who is also the president. What is the proper salutation?**

**A. Dear Mr. Roger Smith****B. Dear Mr. Roger****C. Dear Mr. Smith****D. Dear President Smith**

Ans: C