See-Saw Method for Weighted Averages in Placement Tests
Master the see-saw shortcut for weighted average problems in TCS NQT, AMCAT, and eLitmus. Four worked examples across three question types.
The see-saw method solves weighted average problems without computing the full formula, useful when group sizes arrive as a ratio rather than raw counts.
Placement aptitude tests from TCS NQT to AMCAT include weighted average questions in every full-length test. They appear in three patterns: find the combined average, find what ratio the groups are in, or find a missing group value. One rule handles all three.
The alligation cross that powers the see-saw is derived fully in the mixtures and alligations complete guide. This article is the applied playbook: the rule stated once, then drilled on four placement-exam-style problems.
Where Placement Tests Use Weighted Averages
Weighted average problems appear across the assessment stack that most IT and analytics fresher hiring runs through:
- TCS NQT Numerical Ability — weighted averages appear alongside percentages and ratios in the quantitative section
- AMCAT Quantitative Ability — alligation and average problems are part of the standard question bank
- eLitmus pH Test Quantitative — mixture-and-average problems are a regular fixture
- Mu Sigma MuApt — the Mu Sigma aptitude test emphasises analytical reasoning that includes weighted average reasoning
Time per question in these tests runs from 45 to 75 seconds. A formula approach (multiply, add, divide) uses all of that on a multi-step problem. The see-saw cuts the same problem to 15 to 20 seconds once you practise it.
To understand what other topic areas these tests cover, the campus placement evaluation test guide maps the full syllabus structure. For Mu Sigma specifically, the Mu Sigma MuApt preparation guide covers the test pattern in detail.
The See-Saw Rule
Two groups: Group 1 has n1 members with average A1, Group 2 has n2 members with average A2. The combined average is M. The see-saw rule states:
Think of a physical balance. M is the pivot point. A group with a higher average is like a lighter weight placed farther from the centre, and a larger group pulls the pivot closer to itself. That image keeps the rule stable when exam nerves are high.
- n1 : n2 = (A2 − M) : (M − A1)
Read it as a balance: M is the pivot. The distance from M to each group’s average is inversely proportional to that group’s size. The larger group pulls the combined average closer to itself.
Three things follow from this one rule:
- Given n1, n2, A1, A2 — compute M by solving the proportion
- Given A1, A2, M — read off n1:n2 directly from the two distances
- Given A1, A2, M and one absolute group size — compute the other group size
The full algebraic derivation of why n1:n2 = (A2 − M):(M − A1) is in the mixtures and alligations guide. Do not re-memorise the derivation for exam day. Memorise the identity and practise plugging numbers into it until it is automatic.
Three Question Types in Placement Tests
Type 1: Find the Combined Average
A batch of 25 students scored an average of 72 in the quantitative section. A second batch of 15 scored an average of 88. What is the combined average for all 40 students?
See-saw approach:
- Step 1: Write n1:n2 = 25:15 = 5:3
- Step 2: The gap between the two averages is 88 − 72 = 16
- Step 3: The inverse ratio is 3:5 (swap the digits). M sits 3 parts from A1 and 5 parts from A2, out of a total of 8 parts
- Step 4: M = 72 + (3/8) × 16 = 72 + 6 = 78
Verification (formula):
- (25 × 72 + 15 × 88) / 40 = (1800 + 1320) / 40 = 3120 / 40 = 78 ✓
Type 2: Find the Group Ratio
In a test, Section A candidates averaged 65 and Section B averaged 80. The combined average was 71. What is the ratio of Section A to Section B candidates?
See-saw approach:
- Step 1: Draw the lever: A1 = 65, M = 71, A2 = 80
- Step 2: Distance from M to A1 = 71 − 65 = 6
- Step 3: Distance from M to A2 = 80 − 71 = 9
- Step 4: n_A : n_B = (A2 − M) : (M − A1) = 9 : 6 = 3 : 2
Verification:
- If A = 3 parts and B = 2 parts: (3 × 65 + 2 × 80) / 5 = (195 + 160) / 5 = 355 / 5 = 71 ✓
Type 3: Find a Group Size
In a campus drive, Group X averaged 62 and Group Y averaged 80 on the aptitude test. The combined average was 68 and Group Y had 30 candidates. How many candidates were in Group X?
See-saw approach:
- Step 1: n_X : n_Y = (A_Y − M) : (M − A_X) = (80 − 68) : (68 − 62) = 12 : 6 = 2 : 1
- Step 2: If n_Y = 30 and the ratio is 2:1, then n_X = 2 × 30 = 60
Verification:
- (60 × 62 + 30 × 80) / 90 = (3720 + 2400) / 90 = 6120 / 90 = 68 ✓
The Averaging-the-Averages Trap
The most common error on weighted average questions: taking a simple average when the groups are different sizes.
Two classes, Class A with 40 students averaging 30 kg and Class B with 60 students averaging 40 kg. The wrong approach:
- Simple average = (30 + 40) / 2 = 35 kg (WRONG — treats both classes as equal-sized)
The correct combined average:
- (40 × 30 + 60 × 40) / 100 = (1200 + 2400) / 100 = 36 kg
See-saw check: n1:n2 = 40:60 = 2:3. Distance from M to each average must be in ratio 3:2. Check: (36 − 30) : (40 − 36) = 6 : 4 = 3 : 2. Confirmed.
The simple-average error is off by exactly 1 kg here. On a placement test it’s worth 1 mark. The see-saw eliminates the error by making the group sizes part of the calculation from the first step.
For additional practice on quantitative aptitude topics that appear alongside weighted averages in placement tests, the time and work aptitude guide covers the work-rate shortcuts that follow the same ratio-reasoning structure.
Speed Check: Mastering the Shortcut
To time yourself: all four examples above should take under 20 seconds each once the see-saw is automatic. The order of practice that works:
- Drill Type 2 first (find ratio — the purest application of the rule)
- Then Type 1 with ratio inputs (not raw counts)
- Then Type 3 (reverse-engineer group size)
- Type 1 with raw counts last (the formula is equally fast here, so the see-saw adds less value)
Placement test quantitative sections reward this kind of method-switching: know two approaches to the same problem type, pick the faster one based on how the numbers are given.
The same speed-over-formula thinking applies in AI-era hiring contexts. Recruiters at analytics firms now score candidates on structured problem-solving alongside aptitude scores. If that interests you, TinkerLLM starts at ₹299 and puts practical AI problem-solving in your hands. The ratio-and-proportion reasoning you just drilled maps directly onto how LLM output evaluation works.
Primary sources
Frequently asked questions
What is the see-saw method for weighted averages?
The see-saw method is a visual shortcut based on the alligation cross. Place the two group averages at the ends of a lever and the combined average in the middle. The group sizes are in the inverse ratio of their distances from the combined average.
When should I use the see-saw method instead of the weighted average formula?
Use the see-saw when group sizes are given as a ratio rather than as raw counts, or when you need to find the ratio from a known combined average. The full formula is convenient when all values — both group sizes and both averages — are given as concrete numbers.
Does the see-saw method work for more than two groups?
No. The see-saw applies to exactly two groups. For three or more groups, use the full weighted average formula: sum of (value times weight) divided by sum of weights.
How is the see-saw method related to the alligation cross?
They are the same arithmetic rule. The alligation cross in mixture problems uses the identity n1:n2 = (A2 minus M):(M minus A1). The see-saw is just a balance-point mental image for the same cross — some students find the lever metaphor easier to recall under time pressure.
Which placement tests include weighted average problems?
TCS NQT Numerical Ability, AMCAT Quantitative, eLitmus pH Test, and Mu Sigma MuApt all include weighted average and alligation-type problems. The topic appears in virtually every full-length placement aptitude test from major IT and analytics recruiters.
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